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110x^2+1.1x-25.556=0
a = 110; b = 1.1; c = -25.556;
Δ = b2-4ac
Δ = 1.12-4·110·(-25.556)
Δ = 11245.85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.1)-\sqrt{11245.85}}{2*110}=\frac{-1.1-\sqrt{11245.85}}{220} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.1)+\sqrt{11245.85}}{2*110}=\frac{-1.1+\sqrt{11245.85}}{220} $
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